Advertisements
Advertisements
Question
The value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
Options
True
False
Advertisements
Solution
This statement is True.
Explanation:
Solving it, we get
(a + 1)(a – 1)(a2 + 1) = {(a + 1)(a – 1)} × (a2 + 1)
⇒ (a + 1)(a – 1)(a2 + 1) = (a2 – 1)(a2 + 1) ...[∵ (x + y)(x – y) = x2 – y2; Put x = a and y = 1 ⇒ (a + 1)(a – 1) = a2 – 1]
⇒ (a + 1)(a – 1)(a2 + 1) = a4 – 1 ...[∵ (x2 + y2)(x2 – y2) = x4 – y4; Put x = a and y = 1 ⇒ (a2 + 1)(a2 – 1) = a4 – 1]
Thus, the value of (a + 1)(a – 1)(a2 + 1) is a4 – 1.
APPEARS IN
RELATED QUESTIONS
Expand: 102 x 98
Expand 4p2 – 25q2
Factorise: 4x2 – 9y2
The pathway of a square paddy field has 5 m width and length of its side is 40 m. Find the total area of its pathway. (Note: Use suitable identity)
Using suitable identities, evaluate the following.
(729)2 – (271)2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
4x2 – 49y2
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
`1/36a^2b^2 - 16/49b^2c^2`
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
y4 – 81
Factorise the following using the identity a2 – b2 = (a + b)(a – b).
8a3 – 2a
Factorise the expression and divide them as directed:
(3x2 – 48) ÷ (x – 4)
