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Question
Add:
9ax + 3by – cz, –5by + ax + 3cz
Sum
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Solution
We have,
(9ax + 3by – cz) + (–5by + ax + 3cz)
= 9ax + 3by – cz – 5by + ax + 3cz
= (9ax + ax) + (3by – 5by) + (–cz + 3cz) ...[Grouping like terms]
= 10ax + (–2by) + (2cz)
= 10ax – 2by + 2cz
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Chapter 7: Algebraic Expression, Identities and Factorisation - Exercise [Page 230]
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