Advertisements
Advertisements
Question
ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 46°, find ∠OBC
Advertisements
Solution
Since the diagonals of a rectangle AC and BD are equal and bisect each other
∴ OA = OB
∠OAB = ∠OBA = 46°
Each angle of a rectangle measures 90°
∠ABC = 90°
∠ABO + ∠OBC = 90°
46° + ∠OBC = 90°
∠OBC = 90° − 46°
∴ ∠OBC = 44°
APPEARS IN
RELATED QUESTIONS
Diagonals of a parallelogram ABCD intersect at O. AL and CM are drawn perpendiculars to BD such that L and M lie on BD. Is AL = CM? Why or why not?
Which of the following statement is true for a rectangle?
It has all its sides of equal length.
Which of the following statement is true for a rectangle?
Its diagonals are perpendicular and bisect each other.
Which of the following statement is true for a rectangle?
All rectangles are squares.
Which of the following statement are true for a square?
It has all its sides of equal length.
Which of the following statement true for a square?
Its diagonals are equal to its sides.
In a rectangle ABCD, prove that ∆ACB ≅ ∆CAD.
Using opposite angles test for parallelogram, prove that every rectangle is a parallelogram.
If the diagonals of a parallelogram are of equal lengths, the parallelogram is a rectangle. Prove it.
The following figure is a rectangle in which x: y = 3: 7; find the values of x and y.
