Advertisements
Advertisements
प्रश्न
ABCD is a rectangle whose diagonals AC and BD intersect at O. If ∠OAB = 46°, find ∠OBC
Advertisements
उत्तर
Since the diagonals of a rectangle AC and BD are equal and bisect each other
∴ OA = OB
∠OAB = ∠OBA = 46°
Each angle of a rectangle measures 90°
∠ABC = 90°
∠ABO + ∠OBC = 90°
46° + ∠OBC = 90°
∠OBC = 90° − 46°
∴ ∠OBC = 44°
APPEARS IN
संबंधित प्रश्न
Name the quadrilaterals whose diagonals are equal
ABC is a right-angled triangle and O is the mid point of the side opposite to the right angle. Explain why O is equidistant from A, B and C. (The dotted lines are drawn additionally to help you)
Which of the following statement is true for a rectangle?
It has all its sides of equal length.
Which of the following statement true for a square?
Its diagonals are equal to its sides.
Fill in the blank in the following, so as to make the statement true:
A rectangle is a parallelogram in which .....
The sides of a rectangle are in the ratio 2 : 3, and its perimeter is 20 cm. Draw the rectangle.
Draw a square whose each side measures 4.8 cm.
Using opposite angles test for parallelogram, prove that every rectangle is a parallelogram.
Prove that quadrilateral formed by the intersection of angle bisectors of all angles of a parallelogram is a rectangle.
In a rectangle ABCD, AB = 25 cm and BC = 15. In what ratio does the bisector of ∠C divide AB?
