Advertisements
Advertisements
प्रश्न
The lengths of the diagonals of a Rhombus are 12 cm and 16 cm. Find the side of the rhombus
Advertisements
उत्तर
Since the diagonals of a rhombus bisect each other at right angles
AO = `1/2` AC = `1/2 xx 12` = 6 cm
BO = `1/2` BD = `1/2 xx 16` = 8 cm
In the right triangle AOD
AD2 = AO2 + DO2
= 62 + 82
= 36 + 64
= 100
∴ AD = `sqrt(100)`
= 10
∴ AB = BC = CD = AD = 10 cm.
APPEARS IN
संबंधित प्रश्न
The perimeter of a parallelogram is 150 cm. One of its sides is greater than the other by 25 cm. Find the length of the sides of the parallelogram.
Which of the following statement is true for a rhombus?
It is a parallelogram.
Which of the following statement is true for a rhombus?
It can be a square.
Which of the following statement is true for a rhombus?
It is a square.
The diagonals of a parallelogram are not perpendicular. Is it a rhombus? Why or why not?
Diagonals of a rhombus are 20 cm and 21 cm respectively, then find the side of rhombus and its perimeter.
If opposite angles of a rhombus are (2x)° and (3x - 40)° then value of x is ______.
ABCD is a rhombus. If ∠BAC = 38°, find :
(i) ∠ACB
(ii) ∠DAC
(iii) ∠ADC.

If the diagonal of a rhombus are equal, then the rhombus is a
ABCD is a rhombus such that the perpendicular bisector of AB passes through D. Find the angles of the rhombus.
Hint: Join BD. Then ∆ABD is equilateral.
