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Question
A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?
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Solution
Initially, acceleration of the truck = `("Driving force")/("Mass") = "F"/"M"`
Finally acceleration of the truck
= `("F"//2)/2"M" = 1/4. "F"/"M"`
∴ The acceleration of the truck becomes
`(1/4)^"th"` of its initial value.
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