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प्रश्न
A truck of mass M is moved under a force F. If the truck is then loaded with an object equal to the mass of the truck and the driving force is halved, then how does the acceleration change?
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उत्तर
Initially, acceleration of the truck = `("Driving force")/("Mass") = "F"/"M"`
Finally acceleration of the truck
= `("F"//2)/2"M" = 1/4. "F"/"M"`
∴ The acceleration of the truck becomes
`(1/4)^"th"` of its initial value.
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संबंधित प्रश्न
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| b) Like poles | 2) kg |
| c) Contact force | 3) gravitational force |
| d) Mass | 4) wear and tear |
| e) Weight | 5) force of friction |
| f) Friction | 6) kgf |
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