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Karnataka Board PUCPUC Science 2nd PUC Class 12

A system has two charges qA = 2.5 × 10^−7 C and qB = −2.5 × 10^−7 C located at points A: (0, 0, −15 cm) and B: (0, 0, +15 cm), respectively.

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Question

A system has two charges qA = 2.5 × 10−7 C and qB = −2.5 × 10−7 C located at points A: (0, 0, −15 cm) and B: (0, 0, +15 cm), respectively. What are the total charge and electric dipole moment of the system?

Numerical
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Solution

qnet = qA + qB

qnet = 2.5 × 10−7 + (−2.5 × 10−7)

= 2.5 × 10−7 − 2.5 × 10−7

= 0

Distance between two charges at points A and B,

d = 15 + 15

= 30 cm

= 0.3 m

The electric dipole moment of the system is given by,

p = qA × d = qB × d

= 2.5 × 10−7 × 0.3

= 7.5 × 10−8 C m directed along BA

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Chapter 1: Electric Charge and Fields - EXERCISES [Page 42]

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NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charge and Fields
EXERCISES | Q 1.9 | Page 42
NCERT Physics Part I and II [English] Class 12
Chapter 1 Electric Charges and Fields
Exercise | Q 1.9 | Page 46

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