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Karnataka Board PUCPUC Science 2nd PUC Class 12

A series LCR circuit with R = 20 Ω, L = 1.5 H and C = 35 µF is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, - Physics

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Question

A series LCR circuit with R = 20 Ω, L = 1.5 H and C = 35 µF is connected to a variable-frequency 200 V ac supply. When the frequency of the supply equals the natural frequency of the circuit, what is the average power transferred to the circuit in one complete cycle?

Numerical
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Solution

At resonance, the frequency of the supply power equals the natural frequency of the given LCR circuit.

Resistance, R = 20 Ω

Inductance, L = 1.5 H

Capacitance, C = 35 μF = 35 × 10−6 F

AC supply voltage to the LCR circuit, V = 200 V

Impedance of the circuit is given by the relation,

`"Z" = sqrt("R"^2 + (ω"L" - 1/(ω"C"))^2)`

At resonance, ωL = `1/(ω"C")`

∴ Z = R = 20 Ω

Current in the circuit can be calculated as:

`"I" = "V"/"Z"`

= `200/20`

= 10 A

Hence, the average power transferred to the circuit in one complete cycle = VI = 200 × 10 = 2000 W.

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Chapter 7: Alternating Current - EXERCISES [Page 200]

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NCERT Physics [English] Class 12
Chapter 7 Alternating Current
EXERCISES | Q 7.7 | Page 200

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