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Question
A lever of length 100 cm has the effort of 15 kgf at a distance of 40 cm from the fulcrum at one end. What load can be applied at its other end?
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Solution
Given,
Effort = 15 kgf
Load arm = 100 cm
Effort arm = 40 cm
Mechanical advantage = `"Effort arm "/"Load arm" = 40 /100 = 0.4`
By definition,
Mechanical advantage =`"Load"/"Effort"`
∴ 0.4 = `"Load"/"15 kgf"`
⇒ Load = 15 kgf × 0.4
∴ Load = 6 kgf
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