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Question
A group consists of 4 girls and 7 boys. In how many ways can a team of 5 members be selected if the team has no girls
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Solution
We have 4 girls and 7 boys and a team of 5 members is to be selected.
If no girl is selected, then all the 5 members are to be selected out of 7 boys
i.e. 7C5 = `(7!)/(5!2!)`
= `(7 xx 6.51)/(51 xx 2)`
= 21 ways
Hence the required number of ways are 21 ways.
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