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A company has three jobs on hand. Each of these must be processed through two departments, in the order AB where Department A: Press shop and Department B: Finishing The table below gives the number

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Question

A company has three jobs on hand. Each of these must be processed through two departments, in the order AB where
Department A: Press shop and
Department B: Finishing
The table below gives the number of days required by each job in each department

Job I II III
Department A 8 6 5
Department B 8 3 4

Find the sequence in which the three jobs should be processed so as to take minimum time to finish all the three jobs. Also find idle time for both the departments.

Sum
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Solution

Job I II III
Department A 8 6 5
Department B 8 3 4

Observe that Min(A, B) = 3, corresponds to job II on depatment B.
∴ Job II is placed last in sequence

    II

Then the problem reduces to

Job I III
Department A 8 5
Department B 8 4

Now, Min (A, B) = 4, corresponds to job III on department B.
∴ Job III is placed second in sequence and job I on remaining.
∴ Optimal sequence is

I III II

Total elapsed time.

Job Dept. A Dept. B
In  Out In Out
I (8, 8) 0 8 8 16
III (5, 4) 8 13 16 20
II (6, 3) 13 19 20 23

∴ Total elapsed time = 23 days
Idle time for Department A = 23 – 19 = 4 days
Idle time for Department B = 8 days.

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Types of Sequencing Problem
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Chapter 7: Assignment Problem and Sequencing - Exercise 7.2 [Page 125]

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Balbharati Mathematics and Statistics 2 (Commerce) [English] Standard 12 Maharashtra State Board
Chapter 7 Assignment Problem and Sequencing
Exercise 7.2 | Q 2 | Page 125

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