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1ax2+bx+c

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Question

`1/(ax^2 + bx + c)`

Sum
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Solution

`d/(dx) (1/(ax^2 + bx + c)) = ((ax^2 + bx + c) d/(dx) (1) - 1 * d/(dx) (ax^2 + bx + c))/(ax^2 + bx + c)^2`

= `((ax^2 + bx + x) xx 0 - (2ax + b))/(ac^2 + bx + c)^2`  .....[Using quotient rule]

= `(-(2ax + b))/(ax^2 + bx + c)^2`

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Chapter 13: Limits and Derivatives - Exercise [Page 241]

APPEARS IN

NCERT Exemplar Mathematics Exemplar [English] Class 11
Chapter 13 Limits and Derivatives
Exercise | Q 42 | Page 241

Video TutorialsVIEW ALL [1]

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