मराठी

1ax2+bx+c

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प्रश्न

`1/(ax^2 + bx + c)`

बेरीज
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उत्तर

`d/(dx) (1/(ax^2 + bx + c)) = ((ax^2 + bx + c) d/(dx) (1) - 1 * d/(dx) (ax^2 + bx + c))/(ax^2 + bx + c)^2`

= `((ax^2 + bx + x) xx 0 - (2ax + b))/(ac^2 + bx + c)^2`  .....[Using quotient rule]

= `(-(2ax + b))/(ax^2 + bx + c)^2`

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पाठ 13: Limits and Derivatives - Exercise [पृष्ठ २४१]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 13 Limits and Derivatives
Exercise | Q 42 | पृष्ठ २४१

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