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प्रश्न
`1/(ax^2 + bx + c)`
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उत्तर
`d/(dx) (1/(ax^2 + bx + c)) = ((ax^2 + bx + c) d/(dx) (1) - 1 * d/(dx) (ax^2 + bx + c))/(ax^2 + bx + c)^2`
= `((ax^2 + bx + x) xx 0 - (2ax + b))/(ac^2 + bx + c)^2` .....[Using quotient rule]
= `(-(2ax + b))/(ax^2 + bx + c)^2`
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