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Lim X → 0 Sin 2 X X

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प्रश्न

\[\lim_{x \to 0} \frac{\sin 2x}{x}\] 

विकल्प

  • (a) 0 

  • (b) 1 

  • (c) 1/2 

  • (d) 2 

MCQ
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उत्तर

(d)  2 

\[\lim_{x \to 0} \frac{\sin 2x}{x}\]
\[ = \lim_{x \to 0} 2\left( \frac{\sin 2x}{2x} \right)\]
\[ = 2 \times 1\]
\[ = 2\]

 

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अध्याय 29: Limits - Exercise 29.13 [पृष्ठ ७८]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.13 | Q 2 | पृष्ठ ७८

वीडियो ट्यूटोरियलVIEW ALL [1]

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