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Lim X → ∞ √ X + 1 − √ X - Mathematics

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प्रश्न

\[\lim_{x \to \infty} \sqrt{x + 1} - \sqrt{x}\] 

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उत्तर

\[\lim_{x \to \infty} \left( \sqrt{x + 1} - \sqrt{x} \right)\] 

It is of the form ∞–​​∞.

On rationalising, we get: 

\[\lim_{x \to \infty} \left( \sqrt{x + 1} - \sqrt{x} \right) \times \left( \frac{\sqrt{x + 1} + \sqrt{x}}{\sqrt{x + 1} + \sqrt{x}} \right)\]
\[ = \lim_{x \to \infty} \left( \frac{x + 1 - x}{\left( \sqrt{x + 1} + \sqrt{x} \right)} \right)\]
\[ = \frac{1}{\infty}\]
\[ = 0\] 

 

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अध्याय 29: Limits - Exercise 29.6 [पृष्ठ ३८]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.6 | Q 5 | पृष्ठ ३८

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