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Lim X → − 1 X 3 + 1 X + 1

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प्रश्न

\[\lim_{x \to - 1} \frac{x^3 + 1}{x + 1}\] 

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उत्तर

\[\lim_{x \to - 1} \left[ \frac{x^3 + 1}{x + 1} \right]\]
\[\text{ It is of the form } \frac{0}{0} . \]
\[ \lim_{x \to - 1} \left[ \frac{x^3 + 1^3}{x + 1} \right]\]
\[ = \lim_{x \to - 1} \left[ \frac{\left( x + 1 \right)\left( x^2 - x + 1 \right)}{\left( x + 1 \right)} \right]\]
\[ = \left( - 1 \right)^2 - \left( - 1 \right) + 1\]
\[ = 1 + 1 + 1\]
\[ = 3\]

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अध्याय 29: Limits - Exercise 29.3 [पृष्ठ २३]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.3 | Q 9 | पृष्ठ २३

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