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प्रश्न
\[\lim_{x \to 0} \frac{3x + 1}{x + 3}\]
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उत्तर
\[\lim_{x \to 0} \left( \frac{3x + 1}{x + 3} \right)\]
\[ = \frac{3 \times 0 + 1}{0 + 3}\]
\[ = \frac{1}{3}\]
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