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प्रश्न
\[\lim_{x \to 3} \frac{x^2 - 9}{x + 2}\]
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उत्तर
\[\lim_{x \to 3} \left( \frac{x^2 - 9}{x + 2} \right)\]
\[ = \frac{3^2 - 9}{3 + 2}\]
\[ = \frac{9 - 9}{5}\]
\[ = 0\]
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