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P lim x → 0 sin x n x n

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प्रश्न

\[\lim_{x \to 0} \frac{\sin x^n}{x^n}\] 

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उत्तर

\[\lim_{x \to 0} \frac{\sin x^n}{x^n}\] It is of the form\[\left( \frac{0}{0} \right)\] 

\[\text{ Let } y = x^n \]
\[ \Rightarrow \lim_{x \to 0} = \lim_{y \to 0} \]
\[ \Rightarrow \lim_{y \to 0} \frac{\sin y}{y}\]
\[ \Rightarrow 1 \left\{ \because \lim_{x \to 0} \frac{\sin x}{x} = 1 \right\}\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५०]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 9 | पृष्ठ ५०

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