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Lim X → 0 Sin 3 X 5 X - Mathematics

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प्रश्न

\[\lim_{x \to 0} \frac{\sin 3x}{5x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{\sin 3x}{5x} \right]\]  

=\[\frac{1}{5} \lim_{x \to 0} \left[ \frac{\sin3x}{3x} \times 3 \right]\] 

\[\left[ \because \lim_{x \to 0} \left( \frac{\sin3x}{3x} \right) = 1 \right]\] 

= \[\frac{1}{5} \times 1 \times 3\] 

= \[\frac{3}{5}\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ४९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 1 | पृष्ठ ४९

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