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Lim X → 0 Sin ( 3 + X ) − Sin ( 3 − X ) X

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प्रश्न

\[\lim_{x \to 0} \frac{\sin \left( 3 + x \right) - \sin \left( 3 - x \right)}{x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{\sin \left( 3 + x \right) - \sin \left( 3 - x \right)}{x} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{2 \cos \left( \frac{3 + x + 3 - x}{2} \right) \sin \left( \frac{3 + x - 3 + x}{2} \right)}{x} \right] \left\{ \because \sin C - \sin D = 2 \cos \left( \frac{C + D}{2} \right) \sin \left( \frac{C - D}{2} \right) \right\}\]
\[ = \lim_{x \to 0} \left[ \frac{2 \cos 3 \sin x}{x} \right]\]
\[ = 2 \cos 3\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५०]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 41 | पृष्ठ ५०

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