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प्रश्न
\[\lim_{x \to 0} \frac{2 x^2 + 3x + 4}{x^2 + 3x + 2}\]
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उत्तर
\[\lim_{x \to 0} \left( \frac{2 x^2 + 3x + 4}{x^2 + 3x + 2} \right)\]
\[ = \frac{2 \times 0 + 3 \times 0 + 4}{0 + 3 \times 0 + 2}\]
\[ = \frac{4}{2}\]
\[ = 2\]
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