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Lim X → 0 Sin X Cos X 3 X

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प्रश्न

\[\lim_{x \to 0} \frac{\sin x \cos x}{3x}\] 

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उत्तर

\[\lim_{x \to 0} \left( \frac{\sin x \cos x}{3x} \right)\]

=  \[\frac{1}{3} \lim_{x \to 0} \left( \frac{\sin x}{x} \right) \times \cos x\] 

=  \[\frac{1}{3} \times 1 \times \cos0\]

= \[\frac{1}{3} \times 1\] 

= \[\frac{1}{3}\] 

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ४९]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 4 | पृष्ठ ४९

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