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प्रश्न
\[\lim_{x \to 0} \frac{\sin x \cos x}{3x}\]
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उत्तर
\[\lim_{x \to 0} \left( \frac{\sin x \cos x}{3x} \right)\]
= \[\frac{1}{3} \lim_{x \to 0} \left( \frac{\sin x}{x} \right) \times \cos x\]
= \[\frac{1}{3} \times 1 \times \cos0\]
= \[\frac{1}{3} \times 1\]
= \[\frac{1}{3}\]
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