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प्रश्न
\[\lim_{x \to 0} \frac{3 \sin x - 4 \sin^3 x}{x}\]
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उत्तर
\[\lim_{x \to 0} \left[ \frac{3\sin x - 4 \sin^3 x}{x} \right]\]
= \[\lim_{x \to 0} \left[ \frac{\sin 3x}{x} \right]\] \[\left[ \because \sin^3 A = 3sinA - 4 \sin^3 A \right]\]
= \[\lim_{x \to 0} \left[ \frac{\sin 3x}{3x} \times 3 \right]\]
= 1 × 3
= 3
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