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Lim X → 0 3 Sin X − 4 Sin 3 X X - Mathematics

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प्रश्न

\[\lim_{x \to 0} \frac{3 \sin x - 4 \sin^3 x}{x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{3\sin x - 4 \sin^3 x}{x} \right]\] 

=  \[\lim_{x \to 0} \left[ \frac{\sin 3x}{x} \right]\] \[\left[ \because \sin^3 A = 3sinA - 4 \sin^3 A \right]\]

=  \[\lim_{x \to 0} \left[ \frac{\sin 3x}{3x} \times 3 \right]\] 

= 1 × 3

= 3

 

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५०]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 5 | पृष्ठ ५०

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