मराठी

Evaluate: Lim N → ∞ 1 . 2 + 2 . 3 + 3 . 4 + . . . + N ( N + 1 ) N 3

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प्रश्न

Evaluate: \[\lim_{n \to \infty} \frac{1 . 2 + 2 . 3 + 3 . 4 + . . . + n\left( n + 1 \right)}{n^3}\] 

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उत्तर

\[\lim_{n \to \infty} \frac{1 . 2 + 2 . 3 + 3 . 4 + . . . + n\left( n + 1 \right)}{n^3}\]
\[ = \lim_{n \to \infty} \frac{\sum^n_{k = 1} k\left( k + 1 \right)}{n^3}\]
\[ = \lim_{n \to \infty} \frac{\sum^n_{k = 1} k^2 + \sum^n_{k = 1} k}{n^3}\]
\[ = \lim_{n \to \infty} \frac{\frac{n\left( n + 1 \right)\left( 2n + 1 \right)}{6} + \frac{n\left( n + 1 \right)}{2}}{n^3}\] 

\[= \lim_{n \to \infty} \frac{n\left( n + 1 \right)\left( 2n + 1 + 3 \right)}{6 n^3}\]
\[ = \lim_{n \to \infty} \frac{2n\left( n + 1 \right)\left( n + 2 \right)}{6 n^3}\]
\[ = \frac{1}{3} \lim_{n \to \infty} \left( 1 + \frac{1}{n} \right)\left( 1 + \frac{2}{n} \right)\]
\[ = \frac{1}{3} \times \left( 1 + 0 \right) \times \left( 1 + 0 \right) \left( \lim_{n \to \infty} \frac{1}{n} = 0 \right)\]
\[ = \frac{1}{3}\]

 

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पाठ 29: Limits - Exercise 29.6 [पृष्ठ ३९]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.6 | Q 26 | पृष्ठ ३९

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

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