मराठी

Evaluate limh→0(a+h)2sin(a+h)-a2sinah

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प्रश्न

Evaluate `lim_(h -> 0) ((a + h)^2 sin (a + h) - a^2 sina)/h`

बेरीज
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उत्तर

We have `lim_(h -> 0) ((a + h)^2 sin (a + h) - a^2 sina)/h`

= `lim_(h -> 0) ((a^2 + h^2 + 2ah)[sina cos h + cos a sin h] - a^2 sin a)/h`

= `lim_(h -> 0) [(a^2 sin a (cos h - 1))/h + (a^2 + cos a sin h)/h + (h + 2a) (sin a cos h + cos a sin h)]`

= `lim_(h -> 0) (a^2 sin a (-2sin^2  h/2))/(h^2/2) * h/2 + lim_(h -> 0) (a^2 cos a sin h)/h + lim_(h -> 0) (h + 2a) sin(a + h)`

= `a^2 sin a xx 0 + a^2 cos a(1) + 2a sina`

= `a^2 cos a + 2a sina`.

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पाठ 13: Limits and Derivatives - Solved Examples [पृष्ठ २३४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 13 Limits and Derivatives
Solved Examples | Q 18 | पृष्ठ २३४

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