मराठी

Evaluate limx→0cosax-cosbxcoscx-1

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प्रश्न

Evaluate `lim_(x -> 0) (cos ax - cos bx)/(cos cx - 1)`

बेरीज
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उत्तर

We have `lim_(x -> 0) (2sin  ((a + b))/2 x sin  ((a - b) x)/2)/(2 (sin^2  cx)/2)`

= `lim_(x -> 0) (2sin  ((a + b)x)/2 * sin  ((a - b)x)/2)/x^2 * x^2/(sin^2  (cx)/2)`

= `lim_(x -> 0) (sin  ((a + b)x)/2)/(((a + b)x)/2 * 2/(a + b)) * (sin   ((a - b)x)/2)/(((a - b)x)/2 * 2/(a - b)) * ((cx)^2/2 xx 4/c^2)/(sin^2  (cx)/2)`

= `(a + b)/2 xx (a - b)/2 xx 4/c^2`

= `(a^2 - b^2)/c^2`

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पाठ 13: Limits and Derivatives - Solved Examples [पृष्ठ २३४]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 13 Limits and Derivatives
Solved Examples | Q 17 | पृष्ठ २३४

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