मराठी

Limx→π21-sinxcosx is equal to ______.

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प्रश्न

`lim_(x -> pi/2) (1 - sin x)/cosx` is equal to ______.

पर्याय

  • 0

  • –1

  • 1

  • Does not exit

MCQ
रिकाम्या जागा भरा
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उत्तर

`lim_(x -> pi/2) (1 - sin x)/cosx` is equal to 0.

Explanation:

`lim_(x -> pi/2) (1 - sin x)/cosx`

= `lim_(y -> 0) (1 - sin  pi/2 - y)/(cos  pi/2 - y)` taking ` pi/2 - x = y`

= `lim_(y -> 0) (1 - cos y)/siny`

= `lim_(y -> 0) (2 sin^2  t/2)/(2sin  y/2 cos  y/2)`

= `lim_(y -> 0) tan  y/2`

= 0

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पाठ 13: Limits and Derivatives - Solved Examples [पृष्ठ २३७]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 13 Limits and Derivatives
Solved Examples | Q 23 | पृष्ठ २३७

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