मराठी

Limx→0(sinmxcot x3) = 2, then m = ______.

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प्रश्न

`lim_(x -> 0) (sin mx cot  x/sqrt(3))` = 2, then m = ______. 

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उत्तर

`lim_(x -> 0) (sin mx cot  x/sqrt(3))` = 2, then m = `(2sqrt(2))/3`

Explanation:

Given `lim_(x -> 0) (sin mx cot  x/sqrt(3))` = 2

= `lim_((x -> 0),(because mx -> 0)) (sin mx)/(mx) xx mx  lim_(x -> 0) (cot  x/sqrt(3))` = 2

= `1 xx mx xx lim_(x -> 0) 1/(tan  /sqrt(3))` = 2

= `lim_(x -> 0) mx xx (x/sqrt(3))/(x/sqrt(3) * tan  x/sqrt(3))` = 2

= `(mx)/(x/sqrt(3)) (1)` = 2

⇒ `sqrt(3)m` = 2

⇒ m = `2/sqrt(3) = (2sqrt(3))/3`

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पाठ 13: Limits and Derivatives - Exercise [पृष्ठ २४५]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 13 Limits and Derivatives
Exercise | Q 78 | पृष्ठ २४५

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