मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Evaluate the following limit : limx→0(secx-1x2)

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प्रश्न

Evaluate the following limit :

`lim_(x ->0)((secx - 1)/x^2)`

बेरीज
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उत्तर

`lim_(x ->0)(secx - 1)/x^2`

= `lim_(x -> 0) ((secx - 1)(secx + 1))/(x^2(secx + 1))`

= `lim_(x -> 0) (sec^2 x - 1)/(x^2(secx + 1))`

= `lim_(x -> 0) (tan^2x)/(x^2(secx + 1))`

= `lim_(x -> 0) [(tanx/x)^2 xx 1/(secx + 1)]`

= `lim_(x -> 0) (tanx/x)^2 xx lim_(x -> 0) 1/(secx + 1)`

= `(1)^2 xx 1/(1 + 1)`

= `1/2`

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पाठ 7: Limits - Exercise 7.4 [पृष्ठ १४८]

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