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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Evaluate the following limit : limθ→0[1-cos2θθ2]

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प्रश्न

Evaluate the following limit :

`lim_(theta -> 0) [(1 - cos2theta)/theta^2]`

बेरीज
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उत्तर

`lim_(theta -> 0) (1 - cos2theta)/theta^2`

= `lim_(theta -> 0) (2sin^2theta)/theta^2`

= `2 lim_(theta -> 0) ((sintheta)/theta)^2`

= 2(1)2

= 2

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पाठ 7: Limits - Exercise 7.4 [पृष्ठ १४८]

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