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प्रश्न
Evaluate the following limit :
`lim_(theta -> 0) [(1 - cos2theta)/theta^2]`
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उत्तर
`lim_(theta -> 0) (1 - cos2theta)/theta^2`
= `lim_(theta -> 0) (2sin^2theta)/theta^2`
= `2 lim_(theta -> 0) ((sintheta)/theta)^2`
= 2(1)2
= 2
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