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महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता ११ वी

Select the correct answer from the given alternatives. limx→0(5sinx-xcosx2tanx-3x2) =

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प्रश्न

Select the correct answer from the given alternatives.

`lim_(x -> 0) ((5sinx - xcosx)/(2tanx - 3x^2))` =

पर्याय

  • 0

  • 1

  • 2

  • 3

MCQ
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उत्तर

2

Explanation;

`lim_(x -> 0) ((5sinx - xcosx)/(2tanx - 3x^2))` 

= `(lim_(x -> 0) ((5sinx)/x - cosx))/(lim_(x -> 0) ((2tanx)/x - 3x))`

= `(5(1) - cos0)/(2(1) - 3(0))`

= 2

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  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 7: Limits - Miscellaneous Exercise 7.1 [पृष्ठ १५८]

APPEARS IN

बालभारती Mathematics and Statistics (Arts and Science) Part 2 [English] Standard 11 Maharashtra State Board
पाठ 7 Limits
Miscellaneous Exercise 7.1 | Q I. (6) | पृष्ठ १५८

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