मराठी

Evaluate: limx→0sin22xsin24x

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प्रश्न

Evaluate: `lim_(x -> 0) (sin^2 2x)/(sin^2 4x)`

बेरीज
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उत्तर

Given that `lim_(x -> 0) (sin^2 2x)/(sin^2 4x)`

= `lim_(x -> 0) (sin^2 2x)/(sin^2 2(2x))`

= `lim_(x -> 0) (sin^2 2x)/(4 sin^2 2x * cos^2 2x)`  ......[sin 2x = 2 sin x cos x]

= `1/(4 cos^2 2x)`

Taking limit we have

= `1/(4 * cos^2 0)`

= `1/4`

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पाठ 13: Limits and Derivatives - Exercise [पृष्ठ २४०]

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एनसीईआरटी एक्झांप्लर Mathematics Exemplar [English] Class 11
पाठ 13 Limits and Derivatives
Exercise | Q 16 | पृष्ठ २४०

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