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प्रश्न
Evaluate: `lim_(x -> 3) (x^2 - 9)/(x - 3)`
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उत्तर
Given that `lim_(x -> 3) (x^2 - 9)/(x - 3)`
= `lim_(x -> 3) ((x + 3)(x - 3))/((x - 3))`
= `lim_(x -> 3) x + 3`
Taking limit, we have
3 + 3 = 6
Hence, the answer is 6.
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