मराठी

Evaluate: limx→3x2-9x-3

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प्रश्न

Evaluate: `lim_(x -> 3) (x^2 - 9)/(x - 3)`

बेरीज
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उत्तर

Given that `lim_(x -> 3) (x^2 - 9)/(x - 3)`

= `lim_(x -> 3) ((x + 3)(x - 3))/((x - 3))`

= `lim_(x -> 3) x + 3`

Taking limit, we have

3 + 3 = 6

Hence, the answer is 6.

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पाठ 13: Limits and Derivatives - Exercise [पृष्ठ २३९]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 11
पाठ 13 Limits and Derivatives
Exercise | Q 1 | पृष्ठ २३९

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