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प्रश्न
If `y = 1 + x/(1!) + x^2/(2!) + x^3/(3!) + ...,` then `(dy)/(dx)` = ______.
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उत्तर
Given that `y = 1 + x/(1!) + x^2/(2!) + x^3/(3!) + ...`
`(dy)/(dx) = 0 + 1/(1!) + (2x)/(2!) + (3x^2)/(31) + ...`
= `1 + x/(1!) + x^2/(2!) + x^3/(31) + ...`
= y
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