मराठी

Lim X → 0 3 Sin 2 X − 2 Sin X 2 3 X 2

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प्रश्न

\[\lim_{x \to 0} \frac{3 \sin^2 x - 2 \sin x^2}{3 x^2}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{3 \sin^2 x - 2 \sin x^2}{3 x^2} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{3 \sin^2 x}{3 x^2} - \frac{2 \sin x^2}{3 x^2} \right]\]
\[ = 1 - \frac{2}{3}\]
\[ = \frac{1}{3}\]

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पाठ 29: Limits - Exercise 29.7 [पृष्ठ ५१]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.7 | Q 43 | पृष्ठ ५१

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