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Lim X → 0 Sin 5 X − Sin 3 X Sin X - Mathematics

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प्रश्न

\[\lim_{x \to 0} \frac{\sin 5x - \sin 3x}{\sin x}\] 

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उत्तर

\[\lim_{x \to 0} \left[ \frac{\sin 5x - \sin 3x}{\sin x} \right]\]

\[= \lim_{x \to 0} \left[ \frac{2\cos\left( \frac{5x + 3x}{2} \right)\sin\left( \frac{5x - 3x}{2} \right)}{\sin x} \right] \left[ \because sinC - sinD = 2\cos\left( \frac{C + D}{2} \right)\sin\left( \frac{C - D}{2} \right) \right]\]
\[ = \lim_{x \to 0} \left[ \frac{2\cos4x . \sin x}{\sin x} \right]\]
\[ = 2 \cos0\]
\[ = 2\]

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पाठ 29: Limits - Exercise 29.7 [पृष्ठ ५०]

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आरडी शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.7 | Q 23 | पृष्ठ ५०

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