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Lim X → 0 3 Sin X − Sin 3 X X 3

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प्रश्न

\[\lim_{x \to 0} \frac{3 \sin x - \sin 3x}{x^3}\]

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उत्तर

\[\lim_{x \to 0} \left[ \frac{3 \sin x - \sin \left( 3x \right)}{x^3} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{3 \sin x - \left( 3 \sin x - 4 \sin^3 x \right)}{x^3} \right]\]
\[ = \lim_{x \to 0} \left[ \frac{4 \sin^3 x}{x^3} \right]\]
\[ = \lim_{x \to 0} \left[ 4 \left( \frac{\sin x}{x} \right)^3 \right]\]
\[ = 4 \times 1 = 4\]

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अध्याय 29: Limits - Exercise 29.7 [पृष्ठ ५१]

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आर.डी. शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.7 | Q 56 | पृष्ठ ५१

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