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Lim N → ∞ [ 1 + 2 + 3 . . . . . . N − 1 N 2 ] - Mathematics

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प्रश्न

\[\lim_{n \to \infty} \left[ \frac{1 + 2 + 3 . . . . . . n - 1}{n^2} \right]\] 

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उत्तर

\[\Rightarrow \lim_{n \to \infty} \left( \frac{1 + 2 + 3 + . . . n - 1}{n^2} \right)\]
\[ \Rightarrow \lim_{n \to \infty} \left[ \frac{n\left( n - 1 \right)}{2 n^2} \right]\]
\[ \Rightarrow \lim_{n \to \infty} \left[ \left( 1 - \frac{1}{n} \right) \times \frac{1}{2} \right]\]
\[When n \to \infty , then \frac{1}{n} \to 0 . \]
\[ = \frac{1}{2}\] 

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अध्याय 29: Limits - Exercise 29.6 [पृष्ठ ३९]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.6 | Q 15 | पृष्ठ ३९

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