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Lim X → 0 − Sin [ X ] [ X ] . - Mathematics

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प्रश्न

\[\lim_{x \to 0^-} \frac{\sin \left[ x \right]}{\left[ x \right]} .\] 

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उत्तर

\[\lim_{x \to 0^-} \left( \frac{\sin \left[ x \right]}{\left[ x \right]} \right)\]
\[ x = 0 - h\]
\[ \therefore h \to 0\]
\[ = \lim_{h \to 0} \left( \frac{\sin \left[ 0 - h \right]}{\left[ 0 - h \right]} \right)\]
\[ = \frac{\sin \left( - 1 \right)}{- 1}\]
\[ = \frac{- \sin 1}{- 1}\]
\[ = \sin 1\]

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अध्याय 29: Limits - Exercise 29.12 [पृष्ठ ७७]

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आरडी शर्मा Mathematics [English] Class 11
अध्याय 29 Limits
Exercise 29.12 | Q 5 | पृष्ठ ७७

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