मराठी

Lim X → π 2 Sin 2 X Cos X

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प्रश्न

\[\lim_{x \to \frac{\pi}{2}} \frac{\sin 2x}{\cos x}\] 

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उत्तर

\[\lim_{x \to \frac{\pi}{2}} \frac{\sin 2x}{\cos x} \left[ \sin 2x = 2 \sin x \cos x \right]\]
\[ = \lim_{x \to \frac{\pi}{2}} \frac{2 \sin x \cos x}{\cos x}\]
\[ = \lim_{x \to \frac{\pi}{2}} 2 \sin x\]
\[ \Rightarrow 2\]

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पाठ 29: Limits - Exercise 29.8 [पृष्ठ ६२]

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आर.डी. शर्मा Mathematics [English] Class 11
पाठ 29 Limits
Exercise 29.8 | Q 2 | पृष्ठ ६२

व्हिडिओ ट्यूटोरियलVIEW ALL [1]

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