Advertisements
Advertisements
Question
10 farmers can plough a field in 21 days. Find the number of days reduced if 14 farmers ploughed the same field?
Advertisements
Solution
Let the required number of days if 14 farmers ploughed = x
| Number of days | 21 | x |
| Number of farmers | 10 | 14 |
As number of farmers increases, number of days decreases.
∴ They are in inverse proportion
x1y1 = x2y2
21 × 10 = x × 14
x = `(21 xx 10)/14`
x = 15
Initially the farmers worked for 21 days.
Now they worked for 15 days.
∴ The number of days reduced = 21 – 15 = 6 days
APPEARS IN
RELATED QUESTIONS
In which of the following table x and y vary inversely:
| x | 4 | 3 | 12 | 1 |
| y | 6 | 8 | 2 | 24 |
It x and y vary inversely, fill in the following blank:
| x | 16 | 32 | 8 | 128 |
| y | 4 | ... | ... | 0.25 |
1200 men can finish a stock of food in 35 days. How many more men should join them so that the same stock may last for 25 days?
18 men can reap a field in 35 days. For reaping the same field in 15 days, how many men are required?
Five workers take 12 days to weed a field. How many days would 6 workers take? How many would 15 take?
6 pipes are required to fill a tank in 1 hour 20 minutes. How long will it take if only 5 pipes of the same type are used?
A toy company requires 36 machines to produce car toys in 54 days. How many machines would be required to produce the same number of car toys in 81 days?
If xy = 10, then x and y vary ______ with each other.
A packet of sweets was distributed among 10 children and each of them received 4 sweets. If it is distributed among 8 children, how many sweets will each child get?
The variable x is inversely proportional to y. If x increases by p%, then by what per cent will y decrease?
