Advertisements
Advertisements
प्रश्न
Look at the table. If you were to write the area of each of these which column would you choose? Make a (✓).
| Square cm |
Square meter |
Square km |
|
| Handkerchief | ✓ | ||
| Sari | |||
| Page of your book | |||
| School land | |||
| Total land of a city | |||
| Door of your classroom | |||
| Chair seat | |||
| Blackboard | |||
| Indian flag | |||
| Land over which a river flows |
Advertisements
उत्तर
| Square cm |
Square meter |
Square km |
|
| Handkerchief | ✓ | ||
| Sari | ✓ | ||
| Page of your book | ✓ | ||
| School land | ✓ | ||
| Total land of a city | ✓ | ||
| Door of your classroom | ✓ | ||
| Chair seat | ✓ | ||
| Blackboard | ✓ | ||
| Indian flag | ✓ | ||
| Land over which a river flows | ✓ |
संबंधित प्रश्न
Compute the area of trapezium PQRS is Fig. below.
In the below fig. OCDE is a rectangle inscribed in a quadrant of a circle of radius 10 cm. If
OE = 2√5, find the area of the rectangle.
ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
ABCD is a parallelogram whose diagonals AC and BD intersect at O. A line through O
intersects AB at P and DC at Q. Prove that ar (Δ POA) = ar (Δ QOC).
PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find ar (ΔRAS)
ABCD is a trapezium with parallel sides AB =a and DC = b. If E and F are mid-points of non-parallel sides AD and BC respectively, then the ratio of areas of quadrilaterals ABFEand EFCD is
The mid-points of the sides of a triangle ABC along with any of the vertices as the fourth point make a parallelogram of area equal to ______.
The medians of a triangle ABC intersect each other at point G. If one of its medians is AD,
prove that:
(i) Area ( ΔABD ) = 3 x Area ( ΔBGD )
(ii) Area ( ΔACD ) = 3 x Area ( ΔCGD )
(iii) Area ( ΔBGC ) = `1/3` x Area ( ΔABC ).
The sides of a rectangular park are in the ratio 4 : 3. If its area is 1728 m2, find
(i) its perimeter
(ii) cost of fencing it at the rate of ₹40 per meter.
The length and breadth of a rectangular piece of land are in the ratio 5 : 3. If the total cost of fencing it at the rate of ₹24 per meter is ₹9600, find its :
(i) length and breadth
(ii) area
(iii) cost of levelling at the rate of ₹60 per m2.
Find the area of a rectangle whose length = 8.5 m breadth = 5 m.
The side of a square is 3.6 cm; find its area.
By counting squares, estimate the area of the figure.
Find the area and perimeter of the following parallelograms
The table given below contains some measures of the rectangle. Find the unknown values.
| Length | Breadth | Perimeter | Area |
| 13 cm | ? | 54 cm | ? |
Look at a 10 rupee note. Is its area more than hundred square cm?
In the same way, find the area of piece B.
Is the area of your belt the same as the area of the postcard? Why or why not?
Cheggu’s wife asked him to make a circle with the wire. She knew it had an area of 800 square meters.
- Why did Cheggu not choose a rectangle? Explain.
Each line gives a story. You have to choose the question which makes the best story problem. The first one is already marked.
- 352 children from a school went on a camping trip. Each tent had a group of 4 children.
a) How many children did each tent have? b) How many tents do they need? c) How many children in all are in the school?
Measure the length of the floor of your classroom in meters. Also measure the width.
- If you want to move around easily then how many children do you think should be there in one square meter?
A magazine charges Rs 300 per 10 sq cm area for advertising. A company decided to order a half page advertisment. If each page of the magazine is 15 cm × 24 cm, what amount will the company has to pay for it?
Find all the possible dimensions (in natural numbers) of a rectangle with a perimeter 36 cm and find their areas.
Is the area of both your footprints the same?
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
Find the area of the following figure by counting squares:
