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प्रश्न
The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm is ______.
पर्याय
a rhombus of area 24 cm2
a rectangle of area 24 cm2
a square of area 26 cm2
a trapezium of area 14 cm2
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उत्तर
The figure obtained by joining the mid-points of the adjacent sides of a rectangle of sides 8 cm and 6 cm is a rhombus of area 24 cm2.
Explanation:
Given: Rectangle with sides 8 cm and 6 cm
To find: Area of the figure which is formed by joining the midpoints of the adjacent sides of rectangle.
Calculation: Since we know that area of rhombus = `1/2 (d_1 xx d_2)`
For rhombus EFGH, EG is the one diagonal which is equal to DA
FH is the other diagonal which is equal to AB
Area of rhombus = `1/2 (d_1 xx d_2)`
Area of rhombus = `1/2 ( 8 xx 6)`
Area of rhombus = `1/2 (48)`
Area of rhombus = 24 cm2
संबंधित प्रश्न
Let ABCD be a parallelogram of area 124 cm2. If E and F are the mid-points of sides AB and
CD respectively, then find the area of parallelogram AEFD.
If AD is a median of a triangle ABC, then prove that triangles ADB and ADC are equal in
area. If G is the mid-point of median AD, prove that ar (Δ BGC) = 2 ar (Δ AGC).
ABCD is a parallelogram whose diagonals intersect at O. If P is any point on BO, prove
that: (1) ar (ΔADO) = ar (ΔCDO) (2) ar (ΔABP) = ar (ΔCBP)
P is any point on base BC of ΔABC and D is the mid-point of BC. DE is drawn parallel toPA to meet AC at E. If ar (ΔABC) = 12 cm2, then find area of ΔEPC.
If AD is median of ΔABC and P is a point on AC such that
ar (ΔADP) : ar (ΔABD) = 2 : 3, then ar (Δ PDC) : ar (Δ ABC)
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