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प्रश्न
In the table given below, the information is given about roads. Using this draw a sub-divided and percentage bar diagram (Approximate the percentages to the nearest integer).
| Year | Permanent Roads ( Lakh km.) |
Temporary Roads ( Lakh km.) |
| 2000-2001 | 14 | 10 |
| 2001-2002 | 15 | 11 |
| 2002-2003 | 17 | 13 |
| 2003-2004 | 20 | 19 |
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उत्तर
1. Sub-divided Bar Diagram:
| Year | Permanent Roads (Lakh km.) |
Temporary Roads (Lakh km.) |
Total |
| 2000-2001 | 14 | 10 | 24 |
| 2001-2002 | 15 | 11 | 26 |
| 2002-2003 | 17 | 13 | 30 |
| 2003-2004 | 20 | 19 | 39 |
2. Percentage Bar Diagram:
| Year | Permanent Roads (Lakh km.) |
Percentage of permanent roads | Temporary Roads (Lakh km.) |
Percentage of temporary roads |
| 2000-2001 | 14 | = `14 / (14 + 10)` × 100 = `1400 / 24` = 58.33 ≈ 58 | 10 | = `10/ (14 + 10)` × 100 = `1000 / 24` = 41.66 ≈ 42 |
| 2001-2002 | 15 | = `15 / (15 + 11)` × 100 = `1500 / 26 ` = 57.69 ≈ 58 | 11 | = `11/ (15 + 11)` × 100 = `1100 / 26` = 42.30 ≈ 42 |
| 2002-2003 | 17 | = `17 / (17+13)` × 100 = `1700 / 30` = 56.66 ≈ 57 | 13 | = `13 / (17 + 13)` × 100 = `1300/30` = 43.33 ≈ 43 |
| 2003-2004 | 20 | = `20 / ( 20 + 19)` × 100 = `2000 / 39` = 51.28 ≈ 51 | 19 | = `19/( 20 + 19)` × 100 = `1900/39` = 48.71 ≈ 49 |
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संबंधित प्रश्न
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| Number of children | 135 | 120 | 95 | 100 | 90 | 80 |
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| Watching | 1240 | 470 | 510 | 430 | 250 |
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| Ahmedabad | 38ºC | 29ºC |
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Practice time: Afterschool
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| Reading storybooks | |
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18 |
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| Government School, Chandpur | ||
| Daily Attendance | Date: 15.4.2009 | |
| Class | Total Students | Number of Students Present on that Day |
| VI | 90 | 81 |
| VII | 82 | 76 |
| VIII | 95 | 91 |
| IX | 70 | 65 |
| X | 63 | 62 |
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| Girls | 15 | 24 | 10 | 19 | 27 | 21 |
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