मराठी
महाराष्ट्र राज्य शिक्षण मंडळएचएससी विज्ञान (सामान्य) इयत्ता १२ वी

Evaluate the following : ∫13x2+5x+7.dx

Advertisements
Advertisements

प्रश्न

Evaluate the following : `int (1)/sqrt(3x^2 + 5x + 7).dx`

बेरीज
Advertisements

उत्तर

I = `int1/sqrt(3x^2 + 5x + 7)dx`

I = `1/sqrt3 int 1/sqrt(x^2 + (5x)/3 + 7/3)dx`

I = `1/sqrt3 int 1/sqrt((x^2 + (5x)/3 + 25/36) + (7/3 - 25/36))dx`

I = `1/sqrt3 int 1/sqrt((x^2 + (5x)/3 + (5/6)^2) + (59/36)).dx`

I = `1/sqrt3 int 1/sqrt((x + 5/6)^2 + (sqrt59/6)^2)dx`

I = `1/sqrt3 log |(x + 5/6) +sqrt((x + 5/2)^2 + (sqrt59/6)^2)| + c`   ....`int1/sqrt(x^2 + a^2)dx = log|x + sqrt(x^2 + a^2)| + c`

I = `1/sqrt3 . log|(x + 5/6) + sqrt(x^2 + (5x)/3 + 7/3)| + c` 

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 3: Indefinite Integration - Exercise 3.2 (B) [पृष्ठ १२३]

APPEARS IN

बालभारती Mathematics and Statistics 2 (Arts and Science) [English] Standard 12 Maharashtra State Board
पाठ 3 Indefinite Integration
Exercise 3.2 (B) | Q 1.14 | पृष्ठ १२३

व्हिडिओ ट्यूटोरियलVIEW ALL [2]

संबंधित प्रश्‍न

Evaluate : `int (sinx)/sqrt(36-cos^2x)dx`


Evaluate : `int(x-3)sqrt(x^2+3x-18)  dx`


Integrate the functions:

`(log x)^2/x`


Integrate the functions:

`xsqrt(1+ 2x^2)`


Integrate the functions:

`1/(x(log x)^m),  x > 0, m ne 1`


Evaluate: `int 1/(x(x-1)) dx`


Write a value of\[\int\sqrt{x^2 - 9} \text{ dx}\]


Evaluate : `int ("e"^"x" (1 + "x"))/("cos"^2("x""e"^"x"))"dx"`


Evaluate the following integrals : `int(5x + 2)/(3x - 4).dx`


Integrate the following function w.r.t. x:

`(10x^9 +10^x.log10)/(10^x + x^10)`


Integrate the following functions w.r.t. x : `(2x + 1)sqrt(x + 2)`


Integrate the following functions w.r.t. x:

`x^5sqrt(a^2 + x^2)`


Integrate the following functions w.r.t. x : `(cos3x - cos4x)/(sin3x + sin4x)`


Integrate the following functions w.r.t. x: 

`(1)/(sinx.cosx + 2cos^2x)`


Integrate the following functions w.r.t. x : `(sin6x)/(sin 10x sin 4x)`


Evaluate the following integrals : `int sqrt((9 - x)/x).dx`


`int logx/(log ex)^2*dx` = ______.


Choose the correct options from the given alternatives :

`int (e^(2x) + e^-2x)/e^x*dx` =


Evaluate the following.

`int "x"^5/("x"^2 + 1)`dx


Evaluate the following.

`int ("2x" + 6)/(sqrt("x"^2 + 6"x" + 3))` dx


Evaluate the following.

`int 1/(sqrt(3"x"^2 + 8))` dx


Choose the correct alternative from the following.

`int "x"^2 (3)^("x"^3) "dx"` =


Evaluate `int "x - 1"/sqrt("x + 4")` dx


Evaluate: `int "e"^sqrt"x"` dx


`int sqrt(x)  sec(x)^(3/2) tan(x)^(3/2)"d"x`


`int (1 + x)/(x + "e"^(-x))  "d"x`


`int "dx"/((sin x + cos x)(2 cos x + sin x))` = ?


`int(5x + 2)/(3x - 4) dx` = ______


`int ((x + 1)(x + log x))^4/(3x) "dx" =`______.


If I = `int (sin2x)/(3x + 4cosx)^3 "d"x`, then I is equal to ______.


General solution of `(x + y)^2 ("d"y)/("d"x) = "a"^2, "a" ≠ 0` is ______. (c is arbitrary constant)


`int[ tan (log x) + sec^2 (log x)] dx= ` ______


If f'(x) = `x + 1/x`, then f(x) is ______.


`int(7x - 2)^2dx = (7x -2)^3/21 + c`


`int 1/(sinx.cos^2x)dx` = ______.


`int (logx)^2/x dx` = ______.


Evaluate the following.

`int(20 - 12"e"^"x")/(3"e"^"x" - 4) "dx"`


if `f(x) = 4x^3 - 3x^2 + 2x +k, f (0) = - 1 and f (1) = 4, "find " f(x)`


Evaluate the following.

`int x^3/(sqrt(1 + x^4))dx`


Evaluate `int1/(x(x - 1))dx`


Evaluate `int (1)/(x(x - 1))dx`


Evaluate:

`int sqrt((a - x)/x) dx`


`int (cos4x)/(sin2x + cos2x)dx` = ______.


Evaluate `int (1 + "x" + "x"^2/(2!))`dx


Evaluate `int1/(x(x-1))dx`


Evaluate `int 1/(x(x-1))dx`


If f'(x) = 4x3 – 3x2 + 2x + k, f(0) = 1 and f(1) = 4, find f(x).


Which substitution is appropriate for \[\sqrt{\frac{x}{x-a}}\], \[\sqrt{\frac{x-a}{x}}\], \[\sqrt{x(x-\mathrm{a})}\], or \[\frac{1}{\sqrt{x(x-\mathrm{a})}}\]?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×